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In Fairlawn, there are 5000 households with an average of 2.26 people per household. Of these households, 1400 are single-person households and the rest are multiple-person households.

On average, how many people are in each multiple-person household?

5000 households have average of 2.26 people in total there re  5000*2.26= 11300 people

11300-1400= 9900 people in multiperson households

5000-1400 = 3600 multiperson households

so

9900/3600 = 2.75

So there are an average of 2.75 people in the multiperson households   

What’s the probability that a  #@edited out@#  will post a question and review it to make sure all the information is there? 

Total number of whiskers  =  7 *41  = 287

Take away the one with  17 whiskers  =  270 / 6  =  45 whiskers avg on the other six

slept

Avg for 1st 10 days :

( 84 +88 + 91 + 92 + 96 + 94 + 89 + 78 + 87 + 81) / 10  =

880/10  =

88°  =   

6° above average

For 30 days....if the average temp each day was 80...then the sum of the temps must have been

(30 *80)  =  2400

So......subtracting the sum of the temps for the first 10 days - 880 -  from this we have  =  1520

So....this is the sum of the temps for the last 20 days of the month....so.....the average temp for these days  is just

1520 / 20   =     76°

Prime factorize 2007 to get 3^2 * 223 
This means that there are already 2007 squares in 2007^2007, due to the 3^2. 
Divide 2007 by 2 to get the number of perfect squares for the 223, the second part of the prime factorization. 
2007/2=1003 
After this, you multiply 2007 by 1003, since the prime factorization is 3^2 multiplied by 223. 
2007*1003=2013021 
Then, you add the original 2007, since it it is 2007^2007, so there are 2007 perfect squares right there already for the 3^2 and add 1003 for the perfect squares from 223. 
Add 1 also, because 1 is technically considered to be a perfect square (1*1=1) 

2013021+2007+1003+1=2016032 

Therefore, there are 2016032 factors in 2007^2007 that are perfect squares

Yahoo answers will always be better!

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Then

Total number of people  =  5000 (2.26)   =  11300

Subtract out the 1400 single-person households [1400 people]   and we are left with

[11300 - 1400] persons /  [ 5000 - 1400] households  =

9900 / 3600  =   2.75 people in each multi-person household

14.31 (1.07)   ≈  $ 15.31

9, 13, 15, 17, 19, 23, 31, 49

Mean =22, Median= 18

Remove 19 and 13 and you have:

mean(average) =24 and Median =20

19 x 13 =247

I think... it means surface area... im not sure.. just do surface area

( sorry I was so late )

Average before removal   = ( 9 + 13+ 15+ 17+19+ 23 + 31+ 49)  / 8  = 22

Median before removal =  (17 + 19) / 2  =  18

Avg  after removal  =   24

Median after removal  = 20

19 must have been one of the numbers removed because  (17 + 23) / 2  = 20

So.....if the new average is 24......the sum of the numbers must be 24 * 6  = 144

So....the sum of the 7 numbers after 19 is removed is  157....so......13 must be the other number removed to have a sum of 144

Proof

9,15,17,23,31,49

Average = 24

Median  = 20

So...the product of the removed numbers is    19 * 13   =  247

Thanks! 8/81 Was the right answer! Thanks a bunch!

S  =  35(x - 3)  ..... where  x  is the number put into the kiln and s is the money earned in sales

Same as the first one

S  = 12.99 ( x - 4)       where x is the number of pies made

sorry increased by two i re wrote it.

Increase by  what  ????

Hi Mr Owl,

Chris wants to put six plants in a row on his windowsill. He randomly chooses each plant to be an aloe plant, a basil plant, or a violet. What is the probability that either exactly four of the plants are aloe plants or exactly five of the plants are basil plants?

The number of ways that the 6 plants can be arrangesd is 3^6 = 729

The number of ways that the first 4 plants are aloe vera and the last 2 are not is  1*1*1*1*2*2 = 4

The number of ways that exactly 4 plants are aloe vera is   6C4*4 = 15*4 = 60

The number of ways that the first 5 plants are basil   1*1*1*1*1*2 = 2

The number of ways that the first 5 plants are basil    6C5*2 = 6*2=12

There are no overlaps with these so

The probabity you want is  (60+12) /  729 = 72/729 =   8/81

A  = bh/2      multiply both sides by 2

2A  = bh    divide both sides by b

2A / b  =  h

A  =  (h/₂) ( b₁ + b₂)     multiply both sides by 2/h

2A / h   =   b₁  +  b₂     subtract b2 from each side

2A /h  -  b₂  = b₁

The  midpoint segment is  (1/2)  sum of the parallel bases  = 11cm

So..... the height of the trapezoid  = h

And the height of each separate trapezoid created by the midpoint line  = h/2

Call one of the base lengths x....and the other 22 - x

So call  the area of the smaller trapezoid  =  h ( 11 + x)/2

And the area of the larger trapezoid  = h (11 + [22 - x]) /2  =  h (33 - x)/2

And

(7/4) area of the smaller  = area of the larger....so....

(7/4)h (11 + x) /2  = h(33 - x) /2

(7/4) (11 + x)  =  33 - x

77 + 7x  =  132 - 4x

11x  = 209

x = 19 cm

And the other base  = 22 - 19  = 3cm

So...the product of the bases  = 19 * 3  = 57