In an alternating-current circuit, the voltage E is given by E=IZ, where I is the cirrent (in A) and Z is the impedance.
If I=0.729-0.139j amperes and Z=260+110j ohms, find the complex-number representation.
E = (0.729 - 0.139j) (260+110j)
= 189.54 - 15.29*-1 + 30.69j - 36.14j
= 204.83 - 5.45j
I think that is alright but I could have made a stupid mistake - you had best check it.