Any multiple of the x^4 term will result in a power of x greater than x^3, so you can reduce this to (-3x + 2)^3
The only term that will produce an x^3 is the (-3x) term, so the coefficient of the x^3 term is just (-3)^3 or -27.
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Total marks of boys = 35*50 → 1750
Total marks of girls = 46*gave
Total marks of class = (35 + 46)*40 → 81*40 → 3240
So we must have: 1750 + 46*gave = 3240
46*gave = 3240 - 1750
gave = (3240 - 1750)/46 ≈ 32.4
This might help:
Because it is n/m that you want to get on its own (ie the larger number divided by the smaller one), so you want to get n on its own first.
Let the numbers be n and m, with n > m
n + m = 5(n - m)
Distribute the 5 on the right
n + m = 5n - 5m
Add 5m to both sides
n + 6m = 5n
Subtract n from both sides
6m = 4n
Divide both sides by 4
1.5m = n
Divide both sides by m
1.5 = n/m
or n/m = 1.5. This is the ratio of the larger number to the smaller.
There is nothing in the original expression to indicate that 5(7-5) has been factored from (35 - 25). If it had been the correct way to express the result would have been 60/(5(7 - 5))
60/5(7 - 5) has an implied multiplication so should be read as 60/5*(7-5)
To avoid ambiguity either use parentheses or write as \(\frac{60}{5}(7-5)\text{ or}\frac{60}{5(7-5)}\) as appropriate.
Nor should they have believed you! See my reply #5.
No Gh0sty!
Parentheses first: 60/5*2
Divide and Multiply have the same precedence so you work from left to right:
60/5*2 → 12*2 → 24
The domain refers to all allowable values of x. Here that is from -infinity to + infinity (R)
The range refers to the resulting values of y (or fog(x)). Since (x^2 -1)/(x^2 + 1) can range from -1 (when x is 0) to +1 (when the absolute value of x is very large) then the angle whose cosine is (x^2 -1)/(x^2 + 1) can be any positive or negative value. So the range is -infinity to +infinity as well (R).
"if f(x)=cos^-1(2x-1) and g(x)=x^2/1+x^2 find domain of fog(x)??"
The following should help: