Okay, let me clarify this...
The paper reads:
2) PA = AQ
3) PB = BT
2) O is the centre of the circle if PR is the centre line through the circle
3) BORT is a trapezium
Sorry if there was confusion, I did not realize giving it like it actually was on the paper would or could cause a mis-understanding. From my side, please accept my apologies.
haha...disects!!..oh my goodness!!!..so sorry, that was an honest boo boo...
Also, This exact question I found on the inernet in an exam question paper. The marks allocated for proving ABIIQT, was 2, and for proving the centre, also just 2. Sooo, I'm thinking going the similar triangle way is a lot of work for just 2 marks, HOWEVER, I do aknowledge that the approach given to me was far superior and most likely, the best approach.
Guys, you have all been a great help with this one, I really admire and love you all!!!
I really wish I had the experience you guys have!!..It's good to see how it's solved, however, please if you do not mind....what in my solution makes it wrong?..I understand my approach was wrong, simply because you say it was, and you gave me the appropriate solution....but why is my approach wrong?..would you kindly spend just a little more time please, and just educate me..please...I need to understand this?..You guys are great, thank you for being out there!!
well, honestly....I went about the whole thing a different way...The reason I believe I cannot make use of ratio's, is because I do not have any values. I do not know how one can use ratio's if there are no values....so I did this:
In triangle PQR:
Therefore AO runs through the middel of triangle PQR
Therefore AO devides PR Midpoint theorem
Since PR is the diameter, Given
PO must equal OR
Thus "O" is the middle of the circle.
Is this wrong?..Thanx for your assistance!!
Okay, I think I understand the logic. This approach will ONLY work if and when we have three isosceles triangles forming a parallelogram..if the triangles were anything else, this would not have worked, so it tells me that we will ALWAYS have the angles at 72 and 36 deg's....am I right by making this assumption?
I just wanted to express my gratitude once again for helping me, if I ever learned something new in mathematics, it certainly was this!!..Thank you very much and have a blessed day!
I have gone through your explanation, and I have to admit, I have NOT a clue what you have done, or why you approached the problem the way you did. I have never in my life seen anything like this...What you have done here is absolutely mind-blowing!..I'm trying to follow your steps, but I fail to understand why you did certain things. Anyways, I have double checked my labels, and they are all 100% correct, I have just neglected to say that PQRS was indeed a parallelogram. Sorry about that. Thank you for this extremely dificult explanation....I will be sure to study this, and who knows, maybe one day I'll understand the logic behind this!..Have a great day!!..
Goodness me!!!!...what kind of math is that???..mama mia!!..
Melody, you have really gone the extra mile in trying to help me here!..I do appreciate this soooo much!, But this is my fault actually, because if I had mentioned in the beginning that PQRS was a parallelolgram, I'm sure you would not have spent so much time with this...Please accept my apology.
PES is definitely therefore a straight line...This one really has me speechless!
This is the part that I struggle with, I know ONLY that E1 would also be "x", but that's it...I cannot see how it could be possible at all to determine E3, or any other angle...The handbook gives the answer at the very back, it says E2=72 deg's....how on earth do they get to that?...I guess what I'm going to try is extend some lines and create other angles...maybe that's the way to go...Thanx for replying...
please forgive me if it sounded like I was being childish or..you know, whatever.. i did not mean to laugh at you, i was laughing at myself for not having been able to see the devision could be turned upside down. This is something anyone who has been tutoring maths for some time now, should know, and it should just be in one's face, so to speak...
thank you for teaching me that..once again!!!..have a great day..