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1/cosx(tanx-1)=tanx + cotx/tanx-cotx

plis helpme

Guest Oct 1, 2017
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 #1
avatar+91229 
+1

1/cosx(tanx-1)=tanx + cotx/tanx-cotx

 

You have not used enough brackets, so your question is not clear.

This is what you have asked.  Is it what you really want?

 

\(\frac{1}{cosx(tanx-1)}=tanx + \frac{cotx}{tanx}-cotx\)

Melody  Oct 2, 2017
 #2
avatar+79786 
+1

According to WolframAlpha.....as written, this isn't an identity........

 

I've been trying to find some other arrangement that might "work"  ....but I haven't hit on any, yet.....!!!!

 

 

cool cool cool

CPhill  Oct 2, 2017

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