10 pails of water can fill 5/8 of a tank. Another 4 pails and 5 jugs of water are needed to fill the tank to its brim. How many jugs of water can the tank hold?
+26367 10 pails of water can fill 5/8 of a tank. Another 4 pails and 5 jugs of water are needed to fill the tank to its brim. How many jugs of water can the tank hold ?
$$\dfrac{ \frac{5}{8}\ \mathrm{tank} } { 10\ \mathrm{pails}} * 14 \ \mathrm{pails} = \frac{5*14}{8*10} \ \mathrm{tank} = \frac{7}{8}\ \mathrm{tank} \\\\
\frac{7}{8}\ \mathrm{tank} + 5\ \mathrm{jugs} = 1\ \mathrm{tank} \\
5\ \mathrm{jugs} = 1\ \mathrm{tank}- \frac{7}{8}\ \mathrm{tank} =\frac{1}{8}\ \mathrm{tank} \quad | \quad * 8\\
5*8\ \mathrm{jugs} = \frac{8}{8}\ \mathrm{tank} \\
40\ \mathrm{jugs} = 1\ \mathrm{tank} \\$$
+26367 10 pails of water can fill 5/8 of a tank. Another 4 pails and 5 jugs of water are needed to fill the tank to its brim. How many jugs of water can the tank hold ?
$$\dfrac{ \frac{5}{8}\ \mathrm{tank} } { 10\ \mathrm{pails}} * 14 \ \mathrm{pails} = \frac{5*14}{8*10} \ \mathrm{tank} = \frac{7}{8}\ \mathrm{tank} \\\\
\frac{7}{8}\ \mathrm{tank} + 5\ \mathrm{jugs} = 1\ \mathrm{tank} \\
5\ \mathrm{jugs} = 1\ \mathrm{tank}- \frac{7}{8}\ \mathrm{tank} =\frac{1}{8}\ \mathrm{tank} \quad | \quad * 8\\
5*8\ \mathrm{jugs} = \frac{8}{8}\ \mathrm{tank} \\
40\ \mathrm{jugs} = 1\ \mathrm{tank} \\$$
+128448 Thanks, heureka....here's another way to consider this....
If 10 pails fill 5/8 of the tank, than 10 / (5/8) = 80/5 = 16 pails fill the whole tank.
Then, when 4 more pails are added, 14/16 of the the tank must be filled.
And 5 jugs fill the other 2/16 = 1/8. So, 5/(1/8) = 5 * 8 = 40 jugs fill the whole tank....!!!
