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(16y−4z8)^1/4 /(32y5z−10)^−1/5

 Aug 19, 2015

Best Answer 

 #1
avatar+118609 
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(16y−4z8)^1/4 /(32y5z−10)^−1/5

 

$$(16y-4z8)^{1/4} *(32y5z-10)^{1/5}$$

 Aug 20, 2015
 #1
avatar+118609 
+5
Best Answer

 

(16y−4z8)^1/4 /(32y5z−10)^−1/5

 

$$(16y-4z8)^{1/4} *(32y5z-10)^{1/5}$$

Melody Aug 20, 2015

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