+0  
 
0
1207
1
avatar

2 cos x= sin x+1

 Nov 4, 2014

Best Answer 

 #1
avatar+33614 
+5

Square both sides:

4cos2x = sin2x + 2sinx + 1

 

Replace cos2 by 1 - sin2

4(1 - sin2x) = sin2x + 2sinx + 1

 

Collect terms

5sin2x + 2sinx - 3 = 0

 

This can be written as

(sinx + 5/5)(sinx - 3/5) = 0  or (sinx + 1)(sinx - 3/5) = 0

 

So sinx = -1 and sinx = 3/5

This means x = asin(-1) = 3pi/2 (=270°)

and x = asin(3/5) ≈ 36.87°

 

Adding and subtracting multiples of 2pi (360°) to these also satisfies the original equation.

.

 Nov 4, 2014
 #1
avatar+33614 
+5
Best Answer

Square both sides:

4cos2x = sin2x + 2sinx + 1

 

Replace cos2 by 1 - sin2

4(1 - sin2x) = sin2x + 2sinx + 1

 

Collect terms

5sin2x + 2sinx - 3 = 0

 

This can be written as

(sinx + 5/5)(sinx - 3/5) = 0  or (sinx + 1)(sinx - 3/5) = 0

 

So sinx = -1 and sinx = 3/5

This means x = asin(-1) = 3pi/2 (=270°)

and x = asin(3/5) ≈ 36.87°

 

Adding and subtracting multiples of 2pi (360°) to these also satisfies the original equation.

.

Alan Nov 4, 2014

2 Online Users