If x+15 = 19, evaluate x^3-x^2+16x^-1
Solver by factoring: x^2 -4x-21=0 The two possible solutions possible are in the form of x=a and x=b. Evaluate a^2+b^2+a+b=
Thanks and have a great day! 
+128474 If x + 15 = 19 , then x = 4
So.....x^3-x^2+16x^-1 evaluates to
(4)^3 - (4)^2 + 16/4 =
64 - 16 + 4 =
52
x^2 - 4x - 21 = 0 factor
(x - 7) ( x + 3) = 0
Setting each factor and solving fo x, we have that x =7 or x = -3
So a^2+b^2+a+b = 7^2 + (-3)^2 + 7 - 3 = 62
Thanks to hectictar for catching my error on the second part....!!!!!
