2. The tops of two towers of height x and y standing on level ground,subtend angles of 30° and 60° respectively at the centre of the line joining their feet then find x:y. I need the answer quick

Height of tower x = D tan (30) where D is the distance to the tower from the midway point

Height of tower y = D tan(60)

So.... x : y = D tn (30) / D tan(60) = tan (30) / tan (60) = [ 1 / sqrt (3)] / sqrt (3) =

1 / [ sqrt(3) (sqrt (3)] = 1/3

thank you for the answer!