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2logx+3logx=10

 Aug 5, 2015

Best Answer 

 #1
avatar+118608 
+5

2logx+3logx=10

 

$$\\logx^2+logx^3=10\\\\
log(x^2*x^3)=10\\\\
log(x^5)=10\\\\
10^{log(x^5)}=10^{10}\\\\
x^5=10^{10}\\\\
(x^5)^{1/5}=(10^{10})^{1/5}\\\\
x=10^2\\\\
x=100$$

 

 

OR BETTER STILL

2logx+3logx=10

 

$$\\5logx=10\\\\
logx=2\\\\
x=10^2\\\\
x=100$$

 

BUT why do it the easy way when there is a perfectally good difficult route that can be traversed?   :))

 Aug 5, 2015
 #1
avatar+118608 
+5
Best Answer

2logx+3logx=10

 

$$\\logx^2+logx^3=10\\\\
log(x^2*x^3)=10\\\\
log(x^5)=10\\\\
10^{log(x^5)}=10^{10}\\\\
x^5=10^{10}\\\\
(x^5)^{1/5}=(10^{10})^{1/5}\\\\
x=10^2\\\\
x=100$$

 

 

OR BETTER STILL

2logx+3logx=10

 

$$\\5logx=10\\\\
logx=2\\\\
x=10^2\\\\
x=100$$

 

BUT why do it the easy way when there is a perfectally good difficult route that can be traversed?   :))

Melody Aug 5, 2015

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