3(2x+1)(-x+3)-(2x+5)2=-[-{-3(x+5) }+10x 2].

Alright why not I'll try this one...

Assuming this is the question:

3(2x+1)(-x+3) - (2x+5)² = -[ - { -3(x+5) } + 10x²]

 

(6x+3)(-x+3) - (2x+5)(2x+5) = -[ - { -3x-15 } + 10x²]

 

(-6x² + 15x + 9) - (4x² + 20x + 25) = -[ 3x + 15 + 10x²]

 

-6x² + 15x + 9 - 4x² - 20x - 25 = -3x - 15 - 10x²

 

-10x² - 5x - 16 = -3x - 15 - 10x²

 

-5x - 16 = -3x - 15

 

-5x = -3x + 1

 

-2x = 1

 

x = -1/2