3 numbers: sum of 27 product of 585

Here's one possibilty.....assume all the numbers are integers...one of the numbers must be 5 because a product ending in 5 must have a factor of 5

Dividing 585 / 5  =  117

And 117  can be written as   9 * 13  .......so

Let

a = 5, b = 9, c =13

a + b + c  = 5 + 9 + 13 = 27

a*b*c  = 5 * 9 * 13  = 585