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36X^2+36y^2-24x-12y=31

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36X^2+36y^2-24x-12y=31

Guest Apr 23, 2015

#2
+91432
+10

Do you want to know what shape it is?   Looks like a circle to me.

$$\\36x^2+36y^2-24x-12y=31\\ 36x^2-24x+36y^2-12y=31\\ 36(x^2-\frac{2x}{3}+y^2-\frac{1y}{3})=31\\ (x^2-\frac{2x}{3})+(y^2-\frac{1y}{3})=\frac{31}{36}\\ (x^2-\frac{2x}{3}+\frac{1}{9})+(y^2-\frac{1y}{3}+\frac{1}{36})=\frac{31}{36}+\frac{1}{9}+\frac{1}{36}\\ (x-\frac{1}{3})^2+(y-\frac{1}{6})^2=1\\$$

$$\\Circle:\qquad centre\;(\frac{1}{3},\frac{1}{6})\qquad radius=1\;unit$$

Melody  Apr 24, 2015
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#1
+18827
+10

36x^2+36y^2-24x-12y=31

$$\small{\text{ \begin{array}{rcll} 36x^2+36y^2-24x-12y &=& 31 \\ (36x^2-24x)+(36y^2-12y) &=& 31 \quad & | \quad : 36 \\\\ (x^2-\frac{2}{3}x)+(y^2-\frac{1}{3}y) &=& \frac{31}{36} \\ \\ (x-\frac{2}{6})^2-\frac{4}{36}+(y-\frac{1}{6}y)^2-\frac{1}{36} &=& \frac{31}{36} \\ \\ (x-\frac{1}{3})^2 +(y-\frac{1}{6}y)^2&=& \frac{31}{36} +\frac{4}{36}+\frac{1}{36} \\ \\ (x-\frac{1}{3})^2 +(y-\frac{1}{6}y)^2&=& 1 \\ \\ \end{array} }}$$

This is a circle with center $$\small{\text{ (\frac{1}{3} ,\; \frac{1}{6}) }}$$

heureka  Apr 24, 2015
#2
+91432
+10

Do you want to know what shape it is?   Looks like a circle to me.

$$\\36x^2+36y^2-24x-12y=31\\ 36x^2-24x+36y^2-12y=31\\ 36(x^2-\frac{2x}{3}+y^2-\frac{1y}{3})=31\\ (x^2-\frac{2x}{3})+(y^2-\frac{1y}{3})=\frac{31}{36}\\ (x^2-\frac{2x}{3}+\frac{1}{9})+(y^2-\frac{1y}{3}+\frac{1}{36})=\frac{31}{36}+\frac{1}{9}+\frac{1}{36}\\ (x-\frac{1}{3})^2+(y-\frac{1}{6})^2=1\\$$

$$\\Circle:\qquad centre\;(\frac{1}{3},\frac{1}{6})\qquad radius=1\;unit$$

Melody  Apr 24, 2015
#3
+91432
0

Heureka beat me!     hi Heureka

Melody  Apr 24, 2015

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