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3x^2 + 3 = 0 Solve this equation, considering the i factor.

Guest Mar 3, 2017

Best Answer 

 #2
avatar+1483 
+5

l presume you mean imaginary numbers?

 

3x^2 + 3 =0

 

3x^2 = -3

 

x^2 = -1

 

Since you sqaure root a negative 1 to get x....

 

x = i

HighSchoolCalculus  Mar 3, 2017
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3+0 Answers

 #1
avatar+79894 
+5

3x^2 + 3  = 0      divide through by 3

 

x^2 + 1  = 0        subtract 1 from both sides

 

x^2  =  -1            take the pos/neg roots

 

x  = ±√-1

 

x  =  i      or x = - i

 

 

cool cool cool

CPhill  Mar 3, 2017
 #2
avatar+1483 
+5
Best Answer

l presume you mean imaginary numbers?

 

3x^2 + 3 =0

 

3x^2 = -3

 

x^2 = -1

 

Since you sqaure root a negative 1 to get x....

 

x = i

HighSchoolCalculus  Mar 3, 2017
 #3
avatar+1483 
+5

- i as well

HighSchoolCalculus  Mar 3, 2017

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