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# 4log8sqrt2

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4log8sqrt2
Guest Aug 22, 2015

#3
+91454
+5

If it is base 8 it should have been wrtitten like this

4log_8(sqrt2)

or

4 times the log of sqrt2 base 8

or

$$\\Let\\\\ x=4log_8\sqrt{2}\\\\ x=log_8\sqrt{2}^4\\\\ x=log_8 2^2\\\\ x=log_8 4\\\\ 4=8^x\\\\ 2^2=2^{3x}\\\\ 2=3x\\\\ x=\frac{2}{3}\\\\ 4log_8\sqrt{2}=\frac{2}{3}$$

Melody  Aug 22, 2015
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#1
+91454
+5

Is this base 10 or basse 2?

Alsao I could do with some brackets because I do not known what you are taking the log of  :/

Melody  Aug 22, 2015
#2
+5

This is base 8

$${\mathtt{4}}{\mathtt{\,\times\,}}{log8}{\left({\sqrt{{\mathtt{2}}}}\right)} = {\mathtt{4}}{\mathtt{\,\times\,}}{{log}}_{{\mathtt{8}}}{\left({\mathtt{1.414\: \!213\: \!562\: \!373\: \!095}}\right)}$$

And is this what you mean?

angelo

Guest Aug 22, 2015
#3
+91454
+5

If it is base 8 it should have been wrtitten like this

4log_8(sqrt2)

or

4 times the log of sqrt2 base 8

or

$$\\Let\\\\ x=4log_8\sqrt{2}\\\\ x=log_8\sqrt{2}^4\\\\ x=log_8 2^2\\\\ x=log_8 4\\\\ 4=8^x\\\\ 2^2=2^{3x}\\\\ 2=3x\\\\ x=\frac{2}{3}\\\\ 4log_8\sqrt{2}=\frac{2}{3}$$

Melody  Aug 22, 2015

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