(6x^-2y^4)/2x ?
$$\small{\text{$
\begin{array}{rcl}
\dfrac{ 6 x^{-2} y^4 }{ 2 x } \\\\
&=& \dfrac{ 6 }{ 2 }\cdot \dfrac{ x^{-2} }{ x } \cdot y^4\\\\
&=& 3 \cdot \dfrac{ 1 }{ x^{2}x } \cdot y^4\\\\
&=& 3 \cdot \dfrac{ 1 }{ x^{3} } \cdot y^4\\\\
&=& 3 \cdot \dfrac{ y^4 }{ x^{3} } \\\\
&=& \dfrac{ 3y^4 }{ x^{3} }
\end{array}
$}}$$
(6x^-2y^4)/2x ?
$$\small{\text{$
\begin{array}{rcl}
\dfrac{ 6 x^{-2} y^4 }{ 2 x } \\\\
&=& \dfrac{ 6 }{ 2 }\cdot \dfrac{ x^{-2} }{ x } \cdot y^4\\\\
&=& 3 \cdot \dfrac{ 1 }{ x^{2}x } \cdot y^4\\\\
&=& 3 \cdot \dfrac{ 1 }{ x^{3} } \cdot y^4\\\\
&=& 3 \cdot \dfrac{ y^4 }{ x^{3} } \\\\
&=& \dfrac{ 3y^4 }{ x^{3} }
\end{array}
$}}$$