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8 + y = 8 – y

What is the only value for y that makes this equation true?

Guest May 22, 2017
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\(y=0\)    is the answer

 

Let's look at the original equation:
 

\(8+y=8-y\)

 

To solve this, we must isolate y. This means that we need to get the equation into y equals form. 

 

\(8+y=8-y\) Subtract 8 on both sides

 

If you subtract a number on one side of the equation, you must do that on the other, of course. When you subtract 8 on both sides, you are left with:

 

\(y=-y\)     Add y to both sides

\(y+y=0\)     Combine like terms

\(2y=0\)     Divide by 2 to isolate y

\(y=0\)

 

If you are ever unsure whether an answer is correct or not, plug the value you got back in the original equation:

 

\(8+0=8-0\)

\(8=8\)

 

This statement is true, so y=0 is the correct and the only correct value for y. 

TheXSquaredFactor  May 22, 2017

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