A bicyclist heads east at 18 km/h. After she has traveled 19.2 kilometers another cyclist sets out from the same starting point in the same direction going 30 km/h. How long will it take the second cyclist to catch up to the first cyclist? Explain.
+128474 This is pretty easy to solve and not much math is necessary.
Note that the pursuing cyclist "makes up" (30 - 18) = 12 km every hour.
And since he has to make up 19.2 km, we have
19.2 / 12 = 1.6 hr = 1 hr. 36 min.
^To the person that asked the question, I was on that problem in my Algebra 1 book in the review section in the front… LOL -But what if both of the bicyclists don't stop? The problem says nothing about the first cyclist stopping and waiting for the second cyclist, so wouldn't they just keep going? At that rate, it makes the problem much harder to solve and gets you a whole new set of repeating numbers to work with. My final answer was *approximately* 2 hours and 40 minutes for both of them to meet up at *approximately* 48 kilometers. Now how I got there is a total mess and I'm not even sure if I'm right, but that's my guess. I started by finding the time the second cyclist started their journey which was at around 1 hour 3 minutes and 60 seconds after the first cyclist started. I then drew a graph showing both of the cyclists with time in hours (x) and distance traveled (y). There, you set up a system of equations for both cyclists. To simplify it, I wrote both equations in slope intercept form. So it was y= 18x for the first cyclist and y= 30x - 31.9999... for the second cyclist. I got the y intercept for the second cyclist by solving with the x intercept. Solve the system of equations and I got 2.666... For x. Substitute x in for one of the equations to get the y, 47.999... The solution is (2.666... , 47.999...) 
To anyone out there that just read that, I would appreciate it if you checked my answer, thanks!!!
