A climber is standing at the top of Mount Kazbek, approximately 3.1 mi above sea level. The radius of the Earth is 3959 mi.
What is the climber's distance to the horizon?
Enter your answer as a decimal. Round only your final answer to the nearest tenth.
Answer: 156.7 mi.
We have a right triangle.....
One leg is the radius of the Earth..... and the hypotenuse = Earth's radius + 3.1 miles
The distance to the horizon forms the other leg and is given by
sqrt [ ( 3959 + 3.1)^2 - 3959^2 ] ≈ 156.7 miles