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# Nevermind, I think I got it.

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A climber is standing at the top of Mount Kazbek, approximately 3.1 mi above sea level. The radius of the Earth is 3959 mi.

What is the climber's distance to the horizon?

Gwendolynkristine  Jun 1, 2017
edited by Gwendolynkristine  Jun 1, 2017

#1
+79853
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We have a right triangle.....

One leg is the radius of the Earth.....   and the hypotenuse =  Earth's radius + 3.1 miles

The distance to the horizon forms the other leg and is given by

sqrt [  ( 3959 + 3.1)^2   - 3959^2  ]   ≈  156.7 miles

CPhill  Jun 1, 2017
Sort:

#1
+79853
+2

We have a right triangle.....

One leg is the radius of the Earth.....   and the hypotenuse =  Earth's radius + 3.1 miles

The distance to the horizon forms the other leg and is given by

sqrt [  ( 3959 + 3.1)^2   - 3959^2  ]   ≈  156.7 miles

CPhill  Jun 1, 2017
#2
+79853
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Good job, Gwendolyn....!!!!

CPhill  Jun 1, 2017

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