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# A farmer's dilemma!!.

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Bob rented a farm and agreed to pay \$800 in cash plus a fixed number of bushels of wheat as the yearly rental for his farm. That, he explained, would amount to \$70 an acre when wheat was worth 0.75 cents a bushel. Since wheat is now worth \$1 a bushel, he must pay \$80 an acre, which he thought was too much. What is the size of Bob's farm? Thanks for help.

Guest Mar 11, 2017
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This problem looks familiar. It may have been posted before. However, the solution is relatively easy, if we use a bit of logic. It goes like this:

\$1 - \$0.75 =\$0.25 Difference in price per bushel makes a difference of:
\$80 - \$70 =\$10 an acre in rent. Therefore, the rent paid in wheat is: \$10 / \$0.25 =40 bushels per acre.
40 bushels x \$1 =\$40. So that the rent per acre paid in cash would be:
\$80 - \$40 =\$40 per acre. Hence, the number of acres is:
\$800 / \$40 =20 acres - the size of Bob's farm.

Guest Mar 11, 2017

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