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# A man is 3 times as old as his son. in ten yrs time, the sum of their ages will be 76

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Q.A man is 3 times as old as his son. in ten yrs time, the sum of their ages will be 76. How old was the man when his son was born?

Method below...

(x+10) + (3x+10) = 76

4x + 20 = 76

4x = 76 - 20

4x = 56 , x = 56 / 4 =14

When his son was born, the man was 2x = 2 x 14  28yrs old.

Why would  x = 14 be multiplied by 2?

Guest Mar 18, 2017
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#1
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Note that the son's age now = x =  14

And the father's age is 3x  = 3(14) =  42

So......14 years ago....the father was 42 - 14  = 28 years old

CPhill  Mar 18, 2017
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The BIG question is how old was his son when he was born???    LOL    JK

ElectricPavlov  Mar 18, 2017

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