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A number is "factorific" if the sum of the factorials of each of its digits equals the number itself. Find the only three-digit factorific number.

Recall that a factorial is a product of all the integers from 1 to a specific number. For example $5! = 1\cdot 2 \cdot 3 \cdot 4 \cdot 5$.

 Jul 7, 2015

Best Answer 

 #2
avatar+26367 
+25

A number is "factorific" if the sum of the factorials of each of its digits equals the number itself. Find the only three-digit factorific number.

Recall that a factorial is a product of all the integers from 1 to a specific number. For example $5! = 1\cdot 2 \cdot 3 \cdot 4 \cdot 5$

 

1! = 001

4! = 024

5! = 120

 

1! + 4! + 5! = 145

 

 Jul 9, 2015
 #1
avatar+23246 
+5

1! = 1     2! = 2     3! = 6     4! = 24     5! = 120     6! = 720     7! = too many digits

Adding  1!  to  2!  to  5!  results in 125.

 Jul 7, 2015
 #2
avatar+26367 
+25
Best Answer

A number is "factorific" if the sum of the factorials of each of its digits equals the number itself. Find the only three-digit factorific number.

Recall that a factorial is a product of all the integers from 1 to a specific number. For example $5! = 1\cdot 2 \cdot 3 \cdot 4 \cdot 5$

 

1! = 001

4! = 024

5! = 120

 

1! + 4! + 5! = 145

 

heureka Jul 9, 2015

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