+0

A particular committee needs one -grader and three -graders. If there are four -graders and six -graders applying to the committee, in how m

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146
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A particular committee needs one 7-grader and three 8-graders. If there are four 7-graders and six 8-graders applying to the committee, in how many ways can the committee be filled?

liala  Aug 16, 2017
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#1
+80941
+2

This is a combinations problem

There are 4  seventh graders and we want to choose one of them......

The number of ways this can be done  =  C (4,1) = 4      (1)

There are  six eighth graders and we want to choose any three of them

The number of ways this can be done  = C(8,3)  = 56      (2)

So....the total possible committees  =  (1) * (2)   =  (4) * (56)  =  224

CPhill  Aug 16, 2017
#2
+6
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Thank you soo much CPhil, but unfortunately that isn't the correct answer. I am taking a Probability and Counting class on AOPS like Mellie was....

liala  Aug 17, 2017
#3
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C(4,1) = 4

C(6,3)  = 20

4 * 20 = 60

Guest Aug 17, 2017

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