a pyramid has a square base measuring 10 inches on each side. it has 4 faces that are congruent isosceles triangles. the height of each triangle is 13 inches. find the surface area of the pyramid
There are four triangles each having an area = bh/2 = (10*13)/(2) in2
So......(4)(10*13)/2 in2 = 260 in2
And the area of the base = 102 = 100in2
So...the total surface area = [ 260 + 100]in2 = 360 in2
i have no idea kid sorry