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A recruitment team is required to recruit 9 out of 15 applicant from 3 disciplines,each containing 5 applicants and not required to recruit more than 4 from each disciplines. In how many possible ways can the team make up her choice?

Guest Sep 4, 2014

Best Answer 

 #1
avatar+91404 
+5

I invite comment on this one.  

Let me see...

15 applicants.    5 sportA,     5 sportB    and     5 sportC

9 will be recruited and not more than 4 from any individual sport

possibilities

441      414      144        I think the number here is  5C4*5C4*5C1 = 3* 5*5*5 = 3*125 = 375

432   423  342   324   234   243   I think the number here is  6*5C4*5C3*5C2 = 6*5*10*10=6*500=3000

333    I think the number here is   1* (5C3)^3  =10^3 = 1000

 

So there seems to be 10 ways that the numbers from each sport can be chosen.

I think there are  375+3000+1000=4375 different ways that the 9 can  be selected.      

Melody  Sep 7, 2014
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1+0 Answers

 #1
avatar+91404 
+5
Best Answer

I invite comment on this one.  

Let me see...

15 applicants.    5 sportA,     5 sportB    and     5 sportC

9 will be recruited and not more than 4 from any individual sport

possibilities

441      414      144        I think the number here is  5C4*5C4*5C1 = 3* 5*5*5 = 3*125 = 375

432   423  342   324   234   243   I think the number here is  6*5C4*5C3*5C2 = 6*5*10*10=6*500=3000

333    I think the number here is   1* (5C3)^3  =10^3 = 1000

 

So there seems to be 10 ways that the numbers from each sport can be chosen.

I think there are  375+3000+1000=4375 different ways that the 9 can  be selected.      

Melody  Sep 7, 2014

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