a small rectangular park is being desinged. the perimeter is 340 ft total. the width is 100 ft less than the length. what's the L/W?
Let's set up an equation after defining some variables:
L = length & W = width
W = L - 100 (width is 100 feet less than the length)
Perimeter of a rectangle is 2L + 2W...
2L + 2(L - 100) = 340.
Distribute the 2.
2L + 2L - 200 = 340.
Combine like terms and add 200 to both sides.
4L = 540.
Solve for L.
L = 540/4 = 135.
So, W = L - 100 = 135 - 100 = 35.
L = 135 ft.
W = 35 ft.
Check: 2L + 2W = 340.
2(135) + 2(35) = 340.
270 + 70 = 340. Yes.
Let's set up an equation after defining some variables:
L = length & W = width
W = L - 100 (width is 100 feet less than the length)
Perimeter of a rectangle is 2L + 2W...
2L + 2(L - 100) = 340.
Distribute the 2.
2L + 2L - 200 = 340.
Combine like terms and add 200 to both sides.
4L = 540.
Solve for L.
L = 540/4 = 135.
So, W = L - 100 = 135 - 100 = 35.
L = 135 ft.
W = 35 ft.
Check: 2L + 2W = 340.
2(135) + 2(35) = 340.
270 + 70 = 340. Yes.