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# A very square problem.

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Two squares have a combined area of 68. The side of one square is 4 times the length of the side of the other square. Find the perimeter of each square.

Guest Jun 3, 2017
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Two squares have a combined area of 68. The side of one square is 4 times the length of the side of the other square. Find the perimeter of each square.

Let the side of the 1st. square =S

Then the side of the 2nd. square =4S

Area of 1st. square =S^2

Area of 2nd. square =(4S)^2 =16S^2. But we have:

S^2 + 16S^2 = 68

17S^2 = 68    divide both sides by 17

S^2 =4 take the square root of both sides

S =2 - the side of the 1st. square.

4 x 2 =8 - the perimeter of the 1st. square = the side of the 2nd. square.

8 x 4  =32 - the perimeter of the 2nd. square.

Guest Jun 3, 2017

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