Two squares have a combined area of 68. The side of one square is 4 times the length of the side of the other square. Find the perimeter of each square.
Two squares have a combined area of 68. The side of one square is 4 times the length of the side of the other square. Find the perimeter of each square.
Let the side of the 1st. square =S
Then the side of the 2nd. square =4S
Area of 1st. square =S^2
Area of 2nd. square =(4S)^2 =16S^2. But we have:
S^2 + 16S^2 = 68
17S^2 = 68 divide both sides by 17
S^2 =4 take the square root of both sides
S =2 - the side of the 1st. square.
4 x 2 =8 - the perimeter of the 1st. square = the side of the 2nd. square.
8 x 4 =32 - the perimeter of the 2nd. square.