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# Absolute value graphing stuff

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"If the graph of y=f(x) passes through the point (-1/2,-2/3), then the graph of y=|f(x)| must pass through the point _____."
I don't know how to graph a graph given only one point... :/ I've tried to look stuff up but haven't found anything similar to this problem. I really just don't even know where to start.

Aleguan  Jun 14, 2017

#1
+5552
+2

If  y = f(x)  , we can say this will pass through the point

( x , f(x) )                And they tell us that when  x = -1/2  ,  f(x) = -2/3

( -1/2 , -2/3 )

If  y = | f(x) |  , we can say this will pass through the point

( x , | f(x) | )             And they tell us that when x = -1/2  ,  f(x) = -2/3

( -1/2 , | -2/3 | )

( -1/2 , 2/3 )

I hope this made some sense!

hectictar  Jun 14, 2017
Sort:

#1
+5552
+2

If  y = f(x)  , we can say this will pass through the point

( x , f(x) )                And they tell us that when  x = -1/2  ,  f(x) = -2/3

( -1/2 , -2/3 )

If  y = | f(x) |  , we can say this will pass through the point

( x , | f(x) | )             And they tell us that when x = -1/2  ,  f(x) = -2/3

( -1/2 , | -2/3 | )

( -1/2 , 2/3 )

I hope this made some sense!

hectictar  Jun 14, 2017
#2
+71
+2

Hm. Okay, thanks. That helps. I'm not sure why we switch y with x but I think I'll be able to remember that it's what we do anyways so thanks! :)

Aleguan  Jun 14, 2017
#3
+5552
+2

What do you mean by switch y and x?

The point is still

(x , y)

But since y f(x) , we can replace  " y "  with  " f(x) "

So the point can also be written as

(x , f(x) )

(x , y)  =  (x , f(x) )       if            y = f(x)

I didn't know if that was a confusing part or not.

hectictar  Jun 14, 2017
#4
+71
+2

OHHHHHHHHkay thanks I'm dumb lelel

Aleguan  Jun 14, 2017
#5
+5552
+1

Haha you're not dumb !! Glad you got it now!

hectictar  Jun 14, 2017

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