1. Simplify.
^3√27x^6y^3
Assume all variables are nonnegative.
2. What is the expression in radical form?
(3x^2)^2/3
A. √9x^4
B. √3x^3
C. √3x^4
D. √27x^6
cube root of 27 is 3 cause 3^3=27
can not really simplify the others
3^2/3 is cube root of 9
(x^2)^2/3 is x^4/3 or cube root of x^4
so cube root of 9x^4, i assume A is correct but mistyped?
+2441 \(\sqrt[3]{27x^6y^3}\) can be simplified further.
Let's write all of the variables as numbers to the power of the 3.
\(\sqrt[3]{3^3\left(x^2\right)^3y^3}\)
To make this even easier, i'll distribute the cubed root to every term.
\(\sqrt[3]{3^3}*\sqrt{\left(x^2\right)^3}*\sqrt[3]{y^3}\)
Now, simplify.
\(3x^2y\)
