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# Algebra2

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1. Simplify.

^3√27x^6y^3

Assume all variables are nonnegative.

2. What is the expression in radical form?

(3x^2)^2/3

A. √9x^4

B. √3x^3

C. √3x^4

D. √27x^6

Guest Sep 17, 2017
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#1
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cube root of 27 is 3 cause 3^3=27

can not really simplify the others

3^2/3 is cube root of 9

(x^2)^2/3 is x^4/3 or cube root of x^4

so cube root of 9x^4, i assume A is correct but mistyped?

Guest Sep 17, 2017
#2
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$$\sqrt[3]{27x^6y^3}$$ can be simplified further.

Let's write all of the variables as numbers to the power of the 3.

$$\sqrt[3]{3^3\left(x^2\right)^3y^3}$$

To make this even easier, i'll distribute the cubed root to every term.

$$\sqrt[3]{3^3}*\sqrt{\left(x^2\right)^3}*\sqrt[3]{y^3}$$

Now, simplify.

$$3x^2y$$

TheXSquaredFactor  Sep 17, 2017

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