+0  
 
+1
131
1
avatar+227 

I have a pentagon with side length 7, and I need to know the area. Any help?

liveevillevi  Apr 19, 2017

Best Answer 

 #1
avatar+4749 
+2

 

 

area of pentagon = 10 * area of third triangle

 

area of third triangle = (1/2) * base * height

area of third triangle = (1/2) * 3.5 * (3.5 / tan 36º)

area of third triangle = 6.125 / tan 36º

 

area of pentagon = 10 * 6.125 / tan 36º

area of pentagon = 61.25 / tan 36º

area of pentagon ≈ 84.303 square units

 

*edit*

as long as this is a regular pentagon! :)

hectictar  Apr 19, 2017
edited by hectictar  Apr 19, 2017
Sort: 

1+0 Answers

 #1
avatar+4749 
+2
Best Answer

 

 

area of pentagon = 10 * area of third triangle

 

area of third triangle = (1/2) * base * height

area of third triangle = (1/2) * 3.5 * (3.5 / tan 36º)

area of third triangle = 6.125 / tan 36º

 

area of pentagon = 10 * 6.125 / tan 36º

area of pentagon = 61.25 / tan 36º

area of pentagon ≈ 84.303 square units

 

*edit*

as long as this is a regular pentagon! :)

hectictar  Apr 19, 2017
edited by hectictar  Apr 19, 2017

6 Online Users

avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details