What is the sum of three consecutive even integers if the sum of the first and third integers is $128$?
The numbers would be: 62 + 64 + 66 =192, and 62 + 66 = 128.
Let the first integer = N
So.....the 3rd integer is N + 4
And
N + N + 4 = 128 simplify
2N + 4 = 128 subtract 4 from both sides
2N = 124 divide both sides by 2
N = 62
N + 4 = 66
62 + 66 = 128