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What is the sum of three consecutive even integers if the sum of the first and third integers is $128$?

Guest Sep 10, 2017
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 #1
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The numbers would be: 62 + 64 + 66 =192,  and 62 + 66 = 128.

Guest Sep 10, 2017
 #2
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Let the first integer  = N

 

So.....the 3rd integer is N + 4

 

And

 

N + N + 4 = 128   simplify

 

2N  +  4  =  128       subtract 4 from both sides

 

2N  =  124                divide both sides by 2

 

N  =  62

 

N + 4  =  66

 

62 + 66  =  128

 

 

cool cool cool

CPhill  Sep 10, 2017

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