+502 A length of cable of diameter 1.2mm is under a tension of 150N. Calculate the stress in the cable.
I got 1.33*108 but I am not sure that it is correct or not??
+36916 Stress = F/A Area= pi x r^2 = pi x .6^2 = 1.13 mm^2
F=Force = 150 N (given)
Stress is usually given in Pascals ( N/m^2) so you will need to convert area to m^2
1.13 mm^2 = 11.3 x10^-7 m^2
Stress then becomes F/A = 150 N / (11.3 x 10^-7 m^2) = 132629119 Pascals
So you are correct....but don't forget your UNITS.....Pascals (N/m^2)
+36916 Stress = F/A Area= pi x r^2 = pi x .6^2 = 1.13 mm^2
F=Force = 150 N (given)
Stress is usually given in Pascals ( N/m^2) so you will need to convert area to m^2
1.13 mm^2 = 11.3 x10^-7 m^2
Stress then becomes F/A = 150 N / (11.3 x 10^-7 m^2) = 132629119 Pascals
So you are correct....but don't forget your UNITS.....Pascals (N/m^2)
+36916 Yes.....because this is a VERY thin cable supporting a large force, so the stress is quite high. Good job!
