+0  
 
+1
118
2
avatar+117 

Suppose that you drop a ball from a window 35 meters above the ground. The ball bounces to 80% of its previous height with each bounce. What is the total number of meters (rounded to the nearest tenth) the ball travels between the time it is dropped and the ninth bounce?

 

 232.4 meters

 116.5 meters

 264.2 meters

 268.0 meters

 

It's not C

failurewithasmile  Apr 14, 2017
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2+0 Answers

 #1
avatar+117 
0

@CPhill could you please help me?

failurewithasmile  Apr 14, 2017
 #2
avatar+75362 
+2

We have that the total vertical distance traveled  is :

 

              8

35 + 70 Σ .8^n     =   268.024 m  =  268 m 

              1

 

     

cool cool cool

CPhill  Apr 14, 2017

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