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An airplane is flying at an altitude of 10,000 ft. The airport at which it is scheduled to land is 50 mi away. Find the average angle at which the airplane must descend for landing. Round your answer to the nearest degree.

Kylie335  Mar 10, 2017
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10000 ft = 10000/5280 mi = 1.8939 mi

 

Tan (angle ) = 1.8939 mi / 50 mi = .037878

arctan(.037878) = 2.169 degree angle of descent

ElectricPavlov  Mar 10, 2017

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