big question

how much smaller is 1/h than h

\(h-\frac{1}{h}=\frac{h^2-1}{h}=\frac{(h+1)\times(h-1)}{h}\)

\(\frac{1}{h} \ is \ \frac{h^2-1}{h} \ smaller \ than \ h.\)

This is nonsense but mathematically correct. Or?

  !

It could be asking how many times smaller 1/h is.

It could be asking what you have to multiply 1/h by to get h.

In that case:

(1/h)x=h

x=h²

So you have to multiply 1/h by h² to get h.

1/h is h² times smaller than h.

Either way is possible. I don't really know what the question is asking for.