For what real value of k is \((13-√131)/4 \) a root of \(2x^2-13x+k\)?
The other root will be
(13 + sqrt (131))/ 4
In the form, ax^2 + bx + c......the product of the roots = c / a
So
(13 + sqrt (131))/ 4 * (13 - sqrt (131))/ 4 = k/2
(169 - 131) / 16 = k/2
38/16 = k/2
38/8 = k
