Can you solve log sub base 2 (x+1) + log sub base 2 (x+7) =3 with steps showing how you get to the answer? I get to the log sub base 2 (x+1)(x+7) = 3 but I don't know where to go from there.
+23246 log2(x + 1) + log2(x + 7) = 3
log2[ (x + 1)(x + 7) ] = 3
Simplifying the left side:
log2[ x2 + 8x + 7 ] = 3
Write in exponential form:
x2 + 8x + 7 = 23
x2 + 8x + 7 = 8
x2 + 8x - 1 = 0
Now, finish by using the quadratic formula (You will need to reject imaginary answers and any answer that is less than or equal to 0 (because that will create a log of a non-positive number, which is undefined).)
+23246 log2(x + 1) + log2(x + 7) = 3
log2[ (x + 1)(x + 7) ] = 3
Simplifying the left side:
log2[ x2 + 8x + 7 ] = 3
Write in exponential form:
x2 + 8x + 7 = 23
x2 + 8x + 7 = 8
x2 + 8x - 1 = 0
Now, finish by using the quadratic formula (You will need to reject imaginary answers and any answer that is less than or equal to 0 (because that will create a log of a non-positive number, which is undefined).)
