chromium-48 decays. After 6 half-lives, what fraction of iodine-125 nuclides would be left after 360 days?

Iodine-125 has a half-life of 59.43 days.

R =I . 2^(-360 days/59.43 days), where R=Remainder.

R =I . 2^-6.0575467

R = 0.0150 x 100

R =1.5% - the fraction of Iodine-125 left after 360 days.