+0

# completely factor this expression?

0
171
2

6m^2n - 12mn^2 - 10mn + 20n^2

Guest Jul 20, 2017
Sort:

#1
+18777
+1

completely factor this expression?

6m^2n - 12mn^2 - 10mn + 20n^2

$$\begin{array}{|rcll|} \hline && 6m^2n - 12mn^2 - 10mn + 20n^2 \\ &=& 2n ( 3m^2 - 6mn - 5m + 10n) \\ &=& 2n (m-2n) (3m-5) \\ \hline \end{array}$$

heureka  Jul 20, 2017
#2
0

Factor the following:
6 m^2 n - 12 m n^2 - 10 m n + 20 n^2

Factor 2 n out of 6 m^2 n - 12 m n^2 - 10 m n + 20 n^2:
2 n (3 m^2 - 6 m n - 5 m + 10 n)

Factor terms by grouping. 3 m^2 - 6 m n - 5 m + 10 n = (10 n - 6 m n) + (3 m^2 - 5 m) = m (3 m - 5) - 2 n (3 m - 5):
2 n m (3 m - 5) - 2 n (3 m - 5)

Factor 3 m - 5 from m (3 m - 5) - 2 n (3 m - 5):
Answer: | 2n (3m - 5) (m - 2n)

Guest Jul 20, 2017

### 3 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details