What is the probability that someone random guesses the correct combination in one attempt if the lock has 3 wheels numbered 0-9
+128407
Sorry MG....that's not quite correct....
Assuming that any digit can be repeated.....
We have 10 ways to choose a value in each position.....so the total number of possible combinations =
(10) (10) (10) = 10^3 = 1000
So....the chances that you guess the correct combination one one try = 1 / 1000 = .001 = .1%
+80 Well, there are only 27 possibillities, so, hmm... maybe a
3.7037037037 percentage?(703703703703703 repeating)
Once again, please correct me if I'm wrong.
+128407
Sorry MG....that's not quite correct....
Assuming that any digit can be repeated.....
We have 10 ways to choose a value in each position.....so the total number of possible combinations =
(10) (10) (10) = 10^3 = 1000
So....the chances that you guess the correct combination one one try = 1 / 1000 = .001 = .1%
