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Convert the Cartesian coordinate (2,3) to polar coordinates, 0≤θ<2pi,r>0

r=

θ=

 May 29, 2015

Best Answer 

 #1
avatar+118587 
+15

I am not sure about the 'best, way to do this but

$$\\r=\sqrt{4+9}=\sqrt{13}\\
tan\theta=3/2\\$$

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\mathtt{1.5}}\right)} = {\mathtt{56.309\: \!932\: \!474\: \!02^{\circ}}}$$

 

$$(2,3)\approx(\sqrt{13}, 56.3^0)$$

 

I think that is correct :)

 May 29, 2015
 #1
avatar+118587 
+15
Best Answer

I am not sure about the 'best, way to do this but

$$\\r=\sqrt{4+9}=\sqrt{13}\\
tan\theta=3/2\\$$

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\mathtt{1.5}}\right)} = {\mathtt{56.309\: \!932\: \!474\: \!02^{\circ}}}$$

 

$$(2,3)\approx(\sqrt{13}, 56.3^0)$$

 

I think that is correct :)

Melody May 29, 2015
 #2
avatar+128079 
+5

Good job, Melody.....!!!!...you are correct....

 

 

 May 29, 2015

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