+128460 (sqrt(3) tan x - 3) ( 8cos x + 8) = 0
Either
sqrt (3) tan x - 3 = 0 add 3 to both sides
sqrt (3) tan x = 3 divide both sides by sqrt (3)
tan x = sqrt (3) and this happens at pi/3 and at 4pi/3
Or
8 cos x + 8 = 0 subtract 8 from both sides
8 cos x = -8 divide both sides by 8
cos x = -1 and this happens at pi
pi/3 is correct !!!!!
