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# curious

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$$(36-25)/(16/(\sqrt64{}))$$

Guest Sep 9, 2017
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if it's supposed to be the sqaure root of 64 the answer is $$\frac{11}{16/8} = \frac{11}{2}$$

if it's 4 times the sqare root of 6 the answer is $$\frac{11}{4/\sqrt6}=\frac{11\sqrt6}{4}$$

Jz1234  Sep 9, 2017

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