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What's the derivative of sqrt(3)x^5-6x^4+54*sqrt(7)*x^3+2x^2-5/7x+34.16?

Guest Mar 1, 2017
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 #1
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d/dx (sqrt(3) x^5 - 6 x^4 + 54 sqrt(7) x^3 + 2 x^2 - (5 x)/7 + 34.16) =

 

5 sqrt(3) x^4 - 24 x^3 + 162 sqrt(7) x^2 + 4 x - 5/7

 

cool cool cool

CPhill  Mar 1, 2017
 #2
avatar+18777 
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What's the derivative of sqrt(3)x^5-6x^4+54*sqrt(7)*x^3+2x^2-5/7x+34.16?

 

\(\begin{array}{rcll} && \dfrac{d}{dx}\left(\sqrt{3}\ x^5 - 6 x^4 + 54 \sqrt{7}\ x^3 + 2 x^2 - \frac{5 x}{7} + 34.16 \right) \\\\ &=& 5 \sqrt{3}\ x^4 - 24 x^3 + 162 \sqrt{7}\ x^2 + 4 x - \frac57 \\ \end{array}\)

 

laugh

heureka  Mar 1, 2017

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