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10 logx=-62

find x ??

 Apr 28, 2015

Best Answer 

 #1
avatar+118609 
+5

$$\\10 logx=-62\\
logx=-6.2\\
10^{logx}=10^{-6.2}\\
x=10^{-6.2}\\$$

 

$${{\mathtt{10}}}^{\left(-{\mathtt{6.2}}\right)} = {\mathtt{0.000\: \!000\: \!630\: \!957\: \!344\: \!5}}$$

 

On the web2 calc you do not need to do all that - it will do it for you.  Tricky isn't it.   

 

$${\mathtt{10}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{x}}\right) = -{\mathtt{62}} \Rightarrow {\mathtt{x}} = {{\mathtt{e}}}^{{\mathtt{\,-\,}}\left({\frac{{\mathtt{31}}{\mathtt{\,\times\,}}{ln}{\left({\mathtt{10}}\right)}}{{\mathtt{5}}}}\right)} \Rightarrow {\mathtt{x}} = {\mathtt{0.000\: \!000\: \!630\: \!957\: \!344\: \!5}}$$

.
 Apr 28, 2015
 #1
avatar+118609 
+5
Best Answer

$$\\10 logx=-62\\
logx=-6.2\\
10^{logx}=10^{-6.2}\\
x=10^{-6.2}\\$$

 

$${{\mathtt{10}}}^{\left(-{\mathtt{6.2}}\right)} = {\mathtt{0.000\: \!000\: \!630\: \!957\: \!344\: \!5}}$$

 

On the web2 calc you do not need to do all that - it will do it for you.  Tricky isn't it.   

 

$${\mathtt{10}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{x}}\right) = -{\mathtt{62}} \Rightarrow {\mathtt{x}} = {{\mathtt{e}}}^{{\mathtt{\,-\,}}\left({\frac{{\mathtt{31}}{\mathtt{\,\times\,}}{ln}{\left({\mathtt{10}}\right)}}{{\mathtt{5}}}}\right)} \Rightarrow {\mathtt{x}} = {\mathtt{0.000\: \!000\: \!630\: \!957\: \!344\: \!5}}$$

Melody Apr 28, 2015

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