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determine the gradient k of the straight line passing through the point (4,0) and is perpendicular to the line 4x+17y+3=0. Reply with a shortened fraction k = a/b

 Jul 23, 2016
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Determine the gradient k of the straight line passing through the point (4,0) and is perpendicular to the line 4x+17y+3=0. Reply with a shortened fraction k = a/b

 

First....find the slope of the given line.....

 

4x + 17y + 3  = 0       get y by itself........subtract 17y from both sides

 

4x + 3  = -17y             divide both sides by -17

 

(-4/17)x - 3/17    =  y     the slope of this line is   (-4/17)

 

A line perpendicular to the given one will have a negative reciprocal slope =  17/4

 

So...if k is th gradient, we have that k = 17/4

 

[ The fact that this line passes thorugh (4,0)  does not affect the slope ]

 

 

cool cool cool

 Jul 23, 2016

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