DETERMINE THE RESULTANT VELOCITY OF 75 M/SEC, 25 DEGREES EAST OF NORTH AND 100 M/SEC, 25 DEGREES EAST OF SOUTH
We have two vectors here v1 = < 75cos(65) , 75sin(65) > and v2 = < 100cos(295), 100sin(295) >
Adding the x components, we have 75cos(65) + 100cos(295) = about 73.96
Adding the x components, we have 75sin(65) + 100sin(295) = about -22.66
And the resultant is given by
√[73.962 + (-22.66)2 ] = about 77.35
And the resultant angle is given by
tan-1(-22.66/73.96) = about -17.03° or about S(72.97°)E (using "heading" notation)
We have two vectors here v1 = < 75cos(65) , 75sin(65) > and v2 = < 100cos(295), 100sin(295) >
Adding the x components, we have 75cos(65) + 100cos(295) = about 73.96
Adding the x components, we have 75sin(65) + 100sin(295) = about -22.66
And the resultant is given by
√[73.962 + (-22.66)2 ] = about 77.35
And the resultant angle is given by
tan-1(-22.66/73.96) = about -17.03° or about S(72.97°)E (using "heading" notation)