+0

# Differentiate

0
78
3
+33

2x5-3x4+6x3-2x2 /3x2

Thank you

Ashreeta  Aug 14, 2017
Sort:

#1
+90192
+1

2x5-3x4+6x3-2x2 /3x2

$$\quad\frac{d}{dx}\;\;\frac{2x^5-3x^4+6x^3-2x^2 }{3x^2}\\ =\frac{d}{dx}\;\;\left[\frac{2x^5}{3x^2} - \frac{3x^4}{3x^2} + \frac{ 6x^3}{3x^2} - \frac{2x^2 }{3x^2}\right]\\ =\frac{d}{dx}\;\;\left[\frac{2x^3}{3} - x^2 + 2x - \frac{2 }{3}\right]\\ =\frac{3*2x^2}{3} - 2x + 2 - 0\\ =2x^2-2x+2$$

Melody  Aug 14, 2017
#2
+18564
+1

Differentiate$$\frac{2x^5-3x^4+6x^3-2x^2 }{3x^2}$$

The answer is $$2x^2-2x+2$$

Thank you

$$\begin{array}{|rcll|} \hline y &=& \frac{2x^5-3x^4+6x^3-2x^2 }{3x^2} \\ &=& \frac{x^2 \cdot \left( 2x^3-3x^2+6x-2\right) }{3x^2} \\ &=& \frac{ 2x^3-3x^2+6x-2 }{3} \\ &=& \frac23 x^3-x^2+2x-\frac23 \\\\ y' & = & \frac23\cdot 3x^2 -2x + 2 \\ \mathbf{y'} & \mathbf{=} & \mathbf{2x^2 -2x + 2} \\ \hline \end{array}$$

heureka  Aug 14, 2017
edited by heureka  Aug 14, 2017
#3
+33
+1

Thank you Melody and Heureka

:)

It helped a lot

Ashreeta  Aug 14, 2017

### 10 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details