A number (20000 + 1000A + 300 + 10B + C) is divisible by 22, and A + B + C = 6.
What is the number (20000 + 1000A + 300 + 10B + C)?
There are infinite possibilities.....here's one
A = 2
B = -2
C = 6
So, A + B + C = 6
[20000 + 1000(2) + 300 + 10(-2) + 6] = 22286
And 22286/ 22 = 1013
+425 
